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213011123201209 is a prime number
BaseRepresentation
bin110000011011101110000100…
…010101001110010010111001
31000221012122221102101202101001
4300123232010111032102321
5210404433240014414314
62033011543054525001
762603355130615234
oct6033560425162271
91027178842352331
10213011123201209
1161965567949813
121ba82b96206761
1391b1b2a549958
143a85b1702a41b
151995d94eee674
hexc1bb8454e4b9

213011123201209 has 2 divisors, whose sum is σ = 213011123201210. Its totient is φ = 213011123201208.

The previous prime is 213011123201183. The next prime is 213011123201221. The reversal of 213011123201209 is 902102321110312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 158988696701184 + 54022426500025 = 12609072^2 + 7349995^2 .

It is a cyclic number.

It is not a de Polignac number, because 213011123201209 - 225 = 213011089646777 is a prime.

It is a super-3 number, since 3×2130111232012093 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (213011123201609) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106505561600604 + 106505561600605.

It is an arithmetic number, because the mean of its divisors is an integer number (106505561600605).

Almost surely, 2213011123201209 is an apocalyptic number.

It is an amenable number.

213011123201209 is a deficient number, since it is larger than the sum of its proper divisors (1).

213011123201209 is an equidigital number, since it uses as much as digits as its factorization.

213011123201209 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 28.

The spelling of 213011123201209 in words is "two hundred thirteen trillion, eleven billion, one hundred twenty-three million, two hundred one thousand, two hundred nine".