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213012230122147 is a prime number
BaseRepresentation
bin110000011011101111000110…
…010011110010101010100011
31000221012202210120021011102211
4300123233012103302222203
5210404443021402402042
62033012245000022551
762603424431365051
oct6033570623625243
91027182716234384
10213012230122147
1161965a85760905
121ba83244a61a57
1391b1c75981861
143a85bc004b1d1
151995e0c2a1017
hexc1bbc64f2aa3

213012230122147 has 2 divisors, whose sum is σ = 213012230122148. Its totient is φ = 213012230122146.

The previous prime is 213012230122099. The next prime is 213012230122261. The reversal of 213012230122147 is 741221032210312.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 213012230122147 - 219 = 213012229597859 is a prime.

It is a super-2 number, since 2×2130122301221472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (213012230722147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106506115061073 + 106506115061074.

It is an arithmetic number, because the mean of its divisors is an integer number (106506115061074).

Almost surely, 2213012230122147 is an apocalyptic number.

213012230122147 is a deficient number, since it is larger than the sum of its proper divisors (1).

213012230122147 is an equidigital number, since it uses as much as digits as its factorization.

213012230122147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 31.

Adding to 213012230122147 its reverse (741221032210312), we get a palindrome (954233262332459).

The spelling of 213012230122147 in words is "two hundred thirteen trillion, twelve billion, two hundred thirty million, one hundred twenty-two thousand, one hundred forty-seven".