Base | Representation |
---|---|
bin | 110000011011101111000110… |
… | …010011110010101010100011 |
3 | 1000221012202210120021011102211 |
4 | 300123233012103302222203 |
5 | 210404443021402402042 |
6 | 2033012245000022551 |
7 | 62603424431365051 |
oct | 6033570623625243 |
9 | 1027182716234384 |
10 | 213012230122147 |
11 | 61965a85760905 |
12 | 1ba83244a61a57 |
13 | 91b1c75981861 |
14 | 3a85bc004b1d1 |
15 | 1995e0c2a1017 |
hex | c1bbc64f2aa3 |
213012230122147 has 2 divisors, whose sum is σ = 213012230122148. Its totient is φ = 213012230122146.
The previous prime is 213012230122099. The next prime is 213012230122261. The reversal of 213012230122147 is 741221032210312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213012230122147 - 219 = 213012229597859 is a prime.
It is a super-2 number, since 2×2130122301221472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (213012230722147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106506115061073 + 106506115061074.
It is an arithmetic number, because the mean of its divisors is an integer number (106506115061074).
Almost surely, 2213012230122147 is an apocalyptic number.
213012230122147 is a deficient number, since it is larger than the sum of its proper divisors (1).
213012230122147 is an equidigital number, since it uses as much as digits as its factorization.
213012230122147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 213012230122147 its reverse (741221032210312), we get a palindrome (954233262332459).
The spelling of 213012230122147 in words is "two hundred thirteen trillion, twelve billion, two hundred thirty million, one hundred twenty-two thousand, one hundred forty-seven".
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