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2130131285881 is a prime number
BaseRepresentation
bin11110111111110101101…
…101111111011101111001
321112122020111211002221221
4132333311231333131321
5234400002102122011
64310322510032041
7306616432120054
oct36776555773571
97478214732857
102130131285881
1175142463aa45
122a4a007a8621
13125b416b4a51
1475155571a9b
153a622625971
hex1eff5b7f779

2130131285881 has 2 divisors, whose sum is σ = 2130131285882. Its totient is φ = 2130131285880.

The previous prime is 2130131285839. The next prime is 2130131285911. The reversal of 2130131285881 is 1885821310312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2000753670400 + 129377615481 = 1414480^2 + 359691^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2130131285881 is a prime.

It is a super-2 number, since 2×21301312858812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2130131085881) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065065642940 + 1065065642941.

It is an arithmetic number, because the mean of its divisors is an integer number (1065065642941).

Almost surely, 22130131285881 is an apocalyptic number.

It is an amenable number.

2130131285881 is a deficient number, since it is larger than the sum of its proper divisors (1).

2130131285881 is an equidigital number, since it uses as much as digits as its factorization.

2130131285881 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 92160, while the sum is 43.

The spelling of 2130131285881 in words is "two trillion, one hundred thirty billion, one hundred thirty-one million, two hundred eighty-five thousand, eight hundred eighty-one".