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21302013113 is a prime number
BaseRepresentation
bin10011110101101100…
…101110110010111001
32000222120111101110122
4103311230232302321
5322111303404423
613441440023025
71352612060333
oct236554566271
960876441418
1021302013113
119041481817
124166001a75
132016368cb4
1410611ac453
1584a2078c8
hex4f5b2ecb9

21302013113 has 2 divisors, whose sum is σ = 21302013114. Its totient is φ = 21302013112.

The previous prime is 21302013101. The next prime is 21302013137. The reversal of 21302013113 is 31131020312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19118039824 + 2183973289 = 138268^2 + 46733^2 .

It is a cyclic number.

It is not a de Polignac number, because 21302013113 - 28 = 21302012857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21302013091 and 21302013100.

It is not a weakly prime, because it can be changed into another prime (21302013193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10651006556 + 10651006557.

It is an arithmetic number, because the mean of its divisors is an integer number (10651006557).

Almost surely, 221302013113 is an apocalyptic number.

It is an amenable number.

21302013113 is a deficient number, since it is larger than the sum of its proper divisors (1).

21302013113 is an equidigital number, since it uses as much as digits as its factorization.

21302013113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 21302013113 its reverse (31131020312), we get a palindrome (52433033425).

The spelling of 21302013113 in words is "twenty-one billion, three hundred two million, thirteen thousand, one hundred thirteen".