Base | Representation |
---|---|
bin | 11110111111111010001… |
… | …100111101110000001011 |
3 | 21112122102202101002210111 |
4 | 132333322030331300023 |
5 | 234400130331423222 |
6 | 4310334154255151 |
7 | 306621334420423 |
oct | 36777214756013 |
9 | 7478382332714 |
10 | 2130206514187 |
11 | 7514630520a4 |
12 | 2a4a21a274b7 |
13 | 125b5416423b |
14 | 75161555483 |
15 | 3a629035777 |
hex | 1effa33dc0b |
2130206514187 has 2 divisors, whose sum is σ = 2130206514188. Its totient is φ = 2130206514186.
The previous prime is 2130206514173. The next prime is 2130206514329. The reversal of 2130206514187 is 7814156020312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2130206514187 - 239 = 1580450700299 is a prime.
It is not a weakly prime, because it can be changed into another prime (2130206514127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065103257093 + 1065103257094.
It is an arithmetic number, because the mean of its divisors is an integer number (1065103257094).
Almost surely, 22130206514187 is an apocalyptic number.
2130206514187 is a deficient number, since it is larger than the sum of its proper divisors (1).
2130206514187 is an equidigital number, since it uses as much as digits as its factorization.
2130206514187 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 40.
The spelling of 2130206514187 in words is "two trillion, one hundred thirty billion, two hundred six million, five hundred fourteen thousand, one hundred eighty-seven".
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