2130213001333 has 4 divisors (see below), whose sum is σ = 2136017396800. Its totient is φ = 2124408605868.

The previous prime is 2130213001331. The next prime is 2130213001337. The reversal of 2130213001333 is 3331003120312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2130213001333 - 2¹ = 2130213001331 is a prime.

It is a super-3 number, since 3×2130213001333³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2130213001331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2902197183 + ... + 2902197916.

It is an arithmetic number, because the mean of its divisors is an integer number (534004349200).

Almost surely, 2^{2130213001333} is an apocalyptic number.

It is an amenable number.

2130213001333 is a deficient number, since it is larger than the sum of its proper divisors (5804395467).

2130213001333 is an equidigital number, since it uses as much as digits as its factorization.

2130213001333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5804395466.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 2130213001333 its reverse (3331003120312), we get a palindrome (5461216121645).

The spelling of 2130213001333 in words is "two trillion, one hundred thirty billion, two hundred thirteen million, one thousand, three hundred thirty-three".