Base | Representation |
---|---|
bin | 11110111111111111110… |
… | …101011110011100110001 |
3 | 21112122200100012111100001 |
4 | 132333333311132130301 |
5 | 234400324030114303 |
6 | 4310351412030001 |
7 | 306623562620431 |
oct | 36777765363461 |
9 | 7478610174301 |
10 | 2130301019953 |
11 | 751501430737 |
12 | 2a4a49602301 |
13 | 125b6a903002 |
14 | 7516dd162c1 |
15 | 3a6324a231d |
hex | 1efffd5e731 |
2130301019953 has 2 divisors, whose sum is σ = 2130301019954. Its totient is φ = 2130301019952.
The previous prime is 2130301019941. The next prime is 2130301020037. The reversal of 2130301019953 is 3599101030312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2126600974369 + 3700045584 = 1458287^2 + 60828^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2130301019953 is a prime.
It is a super-2 number, since 2×21303010199532 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2130301019923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065150509976 + 1065150509977.
It is an arithmetic number, because the mean of its divisors is an integer number (1065150509977).
Almost surely, 22130301019953 is an apocalyptic number.
It is an amenable number.
2130301019953 is a deficient number, since it is larger than the sum of its proper divisors (1).
2130301019953 is an equidigital number, since it uses as much as digits as its factorization.
2130301019953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21870, while the sum is 37.
The spelling of 2130301019953 in words is "two trillion, one hundred thirty billion, three hundred one million, nineteen thousand, nine hundred fifty-three".
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