Base | Representation |
---|---|
bin | 11111000000000010001… |
… | …110011111010010001010 |
3 | 21112122210010200100220021 |
4 | 133000002032133102022 |
5 | 234400414312201102 |
6 | 4310355403451054 |
7 | 306624560561431 |
oct | 37000216372212 |
9 | 7478703610807 |
10 | 2130341131402 |
11 | 751522037aa0 |
12 | 2a4a5ab26a8a |
13 | 125b760084b3 |
14 | 75175398118 |
15 | 3a635c77137 |
hex | 1f00239f48a |
2130341131402 has 16 divisors (see below), whose sum is σ = 3491951474592. Its totient is φ = 966687235120.
The previous prime is 2130341131393. The next prime is 2130341131403. The reversal of 2130341131402 is 2041311430312.
It is a super-2 number, since 2×21303411314022 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2130341131403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 82468933 + ... + 82494760.
It is an arithmetic number, because the mean of its divisors is an integer number (218246967162).
Almost surely, 22130341131402 is an apocalyptic number.
2130341131402 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
2130341131402 is a deficient number, since it is larger than the sum of its proper divisors (1361610343190).
2130341131402 is a wasteful number, since it uses less digits than its factorization.
2130341131402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 164964293.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 2130341131402 its reverse (2041311430312), we get a palindrome (4171652561714).
The spelling of 2130341131402 in words is "two trillion, one hundred thirty billion, three hundred forty-one million, one hundred thirty-one thousand, four hundred two".
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