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2130341335 = 5788354049
BaseRepresentation
bin111111011111010…
…0110110111010111
312111110121112220221
41332332212313113
513330331410320
6551220335211
7103535413453
oct17676466727
95443545827
102130341335
119a3581a81
124b5544507
1327c482305
14162d07663
15c705c3aa
hex7efa6dd7

2130341335 has 8 divisors (see below), whose sum is σ = 2556781200. Its totient is φ = 1704025344.

The previous prime is 2130341309. The next prime is 2130341401. The reversal of 2130341335 is 5331430312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2130341335 - 27 = 2130341207 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12391 + ... + 66439.

It is an arithmetic number, because the mean of its divisors is an integer number (319597650).

Almost surely, 22130341335 is an apocalyptic number.

2130341335 is a deficient number, since it is larger than the sum of its proper divisors (426439865).

2130341335 is an equidigital number, since it uses as much as digits as its factorization.

2130341335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61937.

The product of its (nonzero) digits is 3240, while the sum is 25.

The square root of 2130341335 is about 46155.6208386368. The cubic root of 2130341335 is about 1286.7170765222.

Adding to 2130341335 its reverse (5331430312), we get a palindrome (7461771647).

It can be divided in two parts, 213034 and 1335, that added together give a square (214369 = 4632).

The spelling of 2130341335 in words is "two billion, one hundred thirty million, three hundred forty-one thousand, three hundred thirty-five".

Divisors: 1 5 7883 39415 54049 270245 426068267 2130341335