Base | Representation |
---|---|
bin | 11111000000000010110… |
… | …000011110010001001100 |
3 | 21112122210202102222101112 |
4 | 133000002300132101030 |
5 | 234400424102241030 |
6 | 4310400322431152 |
7 | 306625026364430 |
oct | 37000260362114 |
9 | 7478722388345 |
10 | 2130350040140 |
11 | 751527072293 |
12 | 2a4a61b024b8 |
13 | 125b77b0743a |
14 | 751766369c0 |
15 | 3a636936a95 |
hex | 1f002c1e44c |
2130350040140 has 48 divisors (see below), whose sum is σ = 5113862510400. Its totient is φ = 730259668992.
The previous prime is 2130350040083. The next prime is 2130350040187. The reversal of 2130350040140 is 410400530312.
It is a super-2 number, since 2×21303500401402 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 817685 + ... + 2220204.
It is an arithmetic number, because the mean of its divisors is an integer number (106538802300).
Almost surely, 22130350040140 is an apocalyptic number.
2130350040140 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2130350040140 is an abundant number, since it is smaller than the sum of its proper divisors (2983512470260).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2130350040140 is a wasteful number, since it uses less digits than its factorization.
2130350040140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3042914 (or 3042912 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 2130350040140 its reverse (410400530312), we get a palindrome (2540750570452).
The spelling of 2130350040140 in words is "two trillion, one hundred thirty billion, three hundred fifty million, forty thousand, one hundred forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.091 sec. • engine limits •