Base | Representation |
---|---|
bin | 10011110101111001… |
… | …011011010011010101 |
3 | 2000222210202110122221 |
4 | 103311321123103111 |
5 | 322113131404031 |
6 | 13442035222341 |
7 | 1352652261130 |
oct | 236571332325 |
9 | 60883673587 |
10 | 21305341141 |
11 | 9043345157 |
12 | 41671479b1 |
13 | 2016c62a46 |
14 | 10617d7217 |
15 | 84a663a11 |
hex | 4f5e5b4d5 |
21305341141 has 4 divisors (see below), whose sum is σ = 24348961312. Its totient is φ = 18261720972.
The previous prime is 21305341097. The next prime is 21305341151. The reversal of 21305341141 is 14114350312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 21305341141 - 213 = 21305332949 is a prime.
It is a super-2 number, since 2×213053411412 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21305341151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1521810075 + ... + 1521810088.
It is an arithmetic number, because the mean of its divisors is an integer number (6087240328).
Almost surely, 221305341141 is an apocalyptic number.
It is an amenable number.
21305341141 is a deficient number, since it is larger than the sum of its proper divisors (3043620171).
21305341141 is an equidigital number, since it uses as much as digits as its factorization.
21305341141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3043620170.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 21305341141 its reverse (14114350312), we get a palindrome (35419691453).
The spelling of 21305341141 in words is "twenty-one billion, three hundred five million, three hundred forty-one thousand, one hundred forty-one".
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