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213100000313 is a prime number
BaseRepresentation
bin1100011001110110111…
…1111111010000111001
3202101001022020122121012
43012131233333100321
511442412100002223
6241521412323305
721252550054514
oct3063557772071
9671038218535
10213100000313
1182414438342
1235372913535
1317131334855
14a457c3bd7b
15582357ac78
hex319dbff439

213100000313 has 2 divisors, whose sum is σ = 213100000314. Its totient is φ = 213100000312.

The previous prime is 213100000241. The next prime is 213100000357. The reversal of 213100000313 is 313000001312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 167283454009 + 45816546304 = 409003^2 + 214048^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213100000313 is a prime.

It is a super-2 number, since 2×2131000003132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (213100020313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106550000156 + 106550000157.

It is an arithmetic number, because the mean of its divisors is an integer number (106550000157).

Almost surely, 2213100000313 is an apocalyptic number.

It is an amenable number.

213100000313 is a deficient number, since it is larger than the sum of its proper divisors (1).

213100000313 is an equidigital number, since it uses as much as digits as its factorization.

213100000313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 213100000313 its reverse (313000001312), we get a palindrome (526100001625).

Subtracting 213100000313 from its reverse (313000001312), we obtain a palindrome (99900000999).

The spelling of 213100000313 in words is "two hundred thirteen billion, one hundred million, three hundred thirteen", and thus it is an aban number.