Search a number
-
+
213101004121 is a prime number
BaseRepresentation
bin1100011001110111001…
…1110100010101011001
3202101001101010122120021
43012131303310111121
511442412324112441
6241521450030441
721252561435205
oct3063563642531
9671041118507
10213101004121
1182414a63535
1235373118421
13171315c6715
14a45801db05
1558236c83d1
hex319dcf4559

213101004121 has 2 divisors, whose sum is σ = 213101004122. Its totient is φ = 213101004120.

The previous prime is 213101004113. The next prime is 213101004131. The reversal of 213101004121 is 121400101312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 211474898496 + 1626105625 = 459864^2 + 40325^2 .

It is a cyclic number.

It is not a de Polignac number, because 213101004121 - 23 = 213101004113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 213101004095 and 213101004104.

It is not a weakly prime, because it can be changed into another prime (213101004131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106550502060 + 106550502061.

It is an arithmetic number, because the mean of its divisors is an integer number (106550502061).

Almost surely, 2213101004121 is an apocalyptic number.

It is an amenable number.

213101004121 is a deficient number, since it is larger than the sum of its proper divisors (1).

213101004121 is an equidigital number, since it uses as much as digits as its factorization.

213101004121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 213101004121 its reverse (121400101312), we get a palindrome (334501105433).

The spelling of 213101004121 in words is "two hundred thirteen billion, one hundred one million, four thousand, one hundred twenty-one".