Base | Representation |
---|---|
bin | 10011110110001100… |
… | …000010101100111001 |
3 | 2001000010221101201122 |
4 | 103312030002230321 |
5 | 322120404033423 |
6 | 13442331555025 |
7 | 1353041614346 |
oct | 236614025471 |
9 | 61003841648 |
10 | 21310221113 |
11 | 9046078595 |
12 | 41688bba75 |
13 | 2017c80cbc |
14 | 10623077cd |
15 | 84acc98c8 |
hex | 4f6302b39 |
21310221113 has 2 divisors, whose sum is σ = 21310221114. Its totient is φ = 21310221112.
The previous prime is 21310221103. The next prime is 21310221161. The reversal of 21310221113 is 31112201312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14959246864 + 6350974249 = 122308^2 + 79693^2 .
It is a cyclic number.
It is not a de Polignac number, because 21310221113 - 216 = 21310155577 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21310221091 and 21310221100.
It is not a weakly prime, because it can be changed into another prime (21310221103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10655110556 + 10655110557.
It is an arithmetic number, because the mean of its divisors is an integer number (10655110557).
Almost surely, 221310221113 is an apocalyptic number.
It is an amenable number.
21310221113 is a deficient number, since it is larger than the sum of its proper divisors (1).
21310221113 is an equidigital number, since it uses as much as digits as its factorization.
21310221113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 21310221113 its reverse (31112201312), we get a palindrome (52422422425).
The spelling of 21310221113 in words is "twenty-one billion, three hundred ten million, two hundred twenty-one thousand, one hundred thirteen".
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