Base | Representation |
---|---|
bin | 11111000000101010110… |
… | …100100100000100010011 |
3 | 21112201112121020021220011 |
4 | 133000222310210010103 |
5 | 234403313140413412 |
6 | 4310551133255351 |
7 | 306650500560412 |
oct | 37005264440423 |
9 | 7481477207804 |
10 | 2131022201107 |
11 | 751841527818 |
12 | 2a500b034557 |
13 | 125c5414a317 |
14 | 751dba05479 |
15 | 3a67595a7a7 |
hex | 1f02ad24113 |
2131022201107 has 2 divisors, whose sum is σ = 2131022201108. Its totient is φ = 2131022201106.
The previous prime is 2131022201083. The next prime is 2131022201111. The reversal of 2131022201107 is 7011022201312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2131022201107 - 215 = 2131022168339 is a prime.
It is a super-2 number, since 2×21310222011072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2131022201177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065511100553 + 1065511100554.
It is an arithmetic number, because the mean of its divisors is an integer number (1065511100554).
Almost surely, 22131022201107 is an apocalyptic number.
2131022201107 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131022201107 is an equidigital number, since it uses as much as digits as its factorization.
2131022201107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336, while the sum is 22.
Adding to 2131022201107 its reverse (7011022201312), we get a palindrome (9142044402419).
The spelling of 2131022201107 in words is "two trillion, one hundred thirty-one billion, twenty-two million, two hundred one thousand, one hundred seven".
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