2131041004333 has 4 divisors (see below), whose sum is σ = 2146372234720. Its totient is φ = 2115709773948.

The previous prime is 2131041004297. The next prime is 2131041004357. The reversal of 2131041004333 is 3334001401312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2131041004333 - 2⁹ = 2131041003821 is a prime.

It is a super-3 number, since 3×2131041004333³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2131041004298 and 2131041004307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2131041004933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7665614985 + ... + 7665615262.

It is an arithmetic number, because the mean of its divisors is an integer number (536593058680).

Almost surely, 2^{2131041004333} is an apocalyptic number.

It is an amenable number.

2131041004333 is a deficient number, since it is larger than the sum of its proper divisors (15331230387).

2131041004333 is a wasteful number, since it uses less digits than its factorization.

2131041004333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15331230386.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 2131041004333 its reverse (3334001401312), we get a palindrome (5465042405645).

The spelling of 2131041004333 in words is "two trillion, one hundred thirty-one billion, forty-one million, four thousand, three hundred thirty-three".