213111102144433 has 2 divisors, whose sum is σ = 213111102144434. Its totient is φ = 213111102144432.

The previous prime is 213111102144407. The next prime is 213111102144443. The reversal of 213111102144433 is 334441201111312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 210402944804529 + 2708157339904 = 14505273^2 + 1645648^2 .

It is a cyclic number.

It is not a de Polignac number, because 213111102144433 - 2²⁵ = 213111068590001 is a prime.

It is a super-2 number, since 2×213111102144433² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213111102144395 and 213111102144404.

It is not a weakly prime, because it can be changed into another prime (213111102144443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106555551072216 + 106555551072217.

It is an arithmetic number, because the mean of its divisors is an integer number (106555551072217).

Almost surely, 2^{213111102144433} is an apocalyptic number.

It is an amenable number.

213111102144433 is a deficient number, since it is larger than the sum of its proper divisors (1).

213111102144433 is an equidigital number, since it uses as much as digits as its factorization.

213111102144433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 213111102144433 its reverse (334441201111312), we get a palindrome (547552303255745).

The spelling of 213111102144433 in words is "two hundred thirteen trillion, one hundred eleven billion, one hundred two million, one hundred forty-four thousand, four hundred thirty-three".