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2131114130 = 25213111413
BaseRepresentation
bin111111100000110…
…0011100010010010
312111112001210222222
41333001203202102
513331031123010
6551245101042
7103545112505
oct17701434222
95445053888
102131114130
119a3a5a652
124b5857782
1327c692ca2
1416306913c
15c7161355
hex7f063892

2131114130 has 8 divisors (see below), whose sum is σ = 3836005452. Its totient is φ = 852445648.

The previous prime is 2131114129. The next prime is 2131114133. The reversal of 2131114130 is 314111312.

It can be written as a sum of positive squares in 2 ways, for example, as 2025990121 + 105124009 = 45011^2 + 10253^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2131114099 and 2131114108.

It is not an unprimeable number, because it can be changed into a prime (2131114133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106555697 + ... + 106555716.

Almost surely, 22131114130 is an apocalyptic number.

2131114130 is a deficient number, since it is larger than the sum of its proper divisors (1704891322).

2131114130 is a wasteful number, since it uses less digits than its factorization.

2131114130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 213111420.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 2131114130 is about 46163.9917034912. The cubic root of 2131114130 is about 1286.8726460067.

Adding to 2131114130 its reverse (314111312), we get a palindrome (2445225442).

The spelling of 2131114130 in words is "two billion, one hundred thirty-one million, one hundred fourteen thousand, one hundred thirty".

Divisors: 1 2 5 10 213111413 426222826 1065557065 2131114130