Base | Representation |
---|---|
bin | 10011110110010000… |
… | …001010110111001001 |
3 | 2001000012222100221201 |
4 | 103312100022313021 |
5 | 322121143144423 |
6 | 13442411104201 |
7 | 1353054042022 |
oct | 236620126711 |
9 | 61005870851 |
10 | 21311303113 |
11 | 9046747501 |
12 | 4169142061 |
13 | 201826c639 |
14 | 1062509c49 |
15 | 84ae402ad |
hex | 4f640adc9 |
21311303113 has 2 divisors, whose sum is σ = 21311303114. Its totient is φ = 21311303112.
The previous prime is 21311303047. The next prime is 21311303137. The reversal of 21311303113 is 31130311312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21137379769 + 173923344 = 145387^2 + 13188^2 .
It is a cyclic number.
It is not a de Polignac number, because 21311303113 - 217 = 21311172041 is a prime.
It is not a weakly prime, because it can be changed into another prime (21311303813) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10655651556 + 10655651557.
It is an arithmetic number, because the mean of its divisors is an integer number (10655651557).
Almost surely, 221311303113 is an apocalyptic number.
It is an amenable number.
21311303113 is a deficient number, since it is larger than the sum of its proper divisors (1).
21311303113 is an equidigital number, since it uses as much as digits as its factorization.
21311303113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 21311303113 its reverse (31130311312), we get a palindrome (52441614425).
The spelling of 21311303113 in words is "twenty-one billion, three hundred eleven million, three hundred three thousand, one hundred thirteen".
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