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213113120000 = 285411196373
BaseRepresentation
bin1100011001111010001…
…0000010010100000000
3202101002012221012102112
43012132202002110000
511442423424320000
6241523001434452
721253066426364
oct3063642022400
9671065835375
10213113120000
1182420889360
123537719ba28
1317133c79391
14a4598952a4
1558247bd235
hex319e882500

213113120000 has 360 divisors, whose sum is σ = 610513448160. Its totient is φ = 73405440000.

The previous prime is 213113119997. The next prime is 213113120023. The reversal of 213113120000 is 21311312.

It is a super-2 number, since 2×2131131200002 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 33436814 + ... + 33443186.

Almost surely, 2213113120000 is an apocalyptic number.

213113120000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 213113120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (305256724080).

213113120000 is an abundant number, since it is smaller than the sum of its proper divisors (397400328160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213113120000 is an equidigital number, since it uses as much as digits as its factorization.

213113120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6439 (or 6410 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 213113120000 its reverse (21311312), we get a palindrome (213134431312).

213113120000 divided by its reverse (21311312) gives a 4-th power (10000 = 104).

It can be divided in two parts, 2131 and 13120000, that added together give a palindrome (13122131).

The spelling of 213113120000 in words is "two hundred thirteen billion, one hundred thirteen million, one hundred twenty thousand".