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213113210131 is a prime number
BaseRepresentation
bin1100011001111010001…
…0011000010100010011
3202101002020002210001201
43012132202120110103
511442423440211011
6241523003412031
721253100253223
oct3063642302423
9671066083051
10213113210131
1182420940048
1235377224017
1317133cab403
14a4598ba083
1558247d9cc1
hex319e898513

213113210131 has 2 divisors, whose sum is σ = 213113210132. Its totient is φ = 213113210130.

The previous prime is 213113210087. The next prime is 213113210137. The reversal of 213113210131 is 131012311312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 213113210131 - 211 = 213113208083 is a prime.

It is a super-2 number, since 2×2131132101312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213113210099 and 213113210108.

It is not a weakly prime, because it can be changed into another prime (213113210137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106556605065 + 106556605066.

It is an arithmetic number, because the mean of its divisors is an integer number (106556605066).

Almost surely, 2213113210131 is an apocalyptic number.

213113210131 is a deficient number, since it is larger than the sum of its proper divisors (1).

213113210131 is an equidigital number, since it uses as much as digits as its factorization.

213113210131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 213113210131 its reverse (131012311312), we get a palindrome (344125521443).

The spelling of 213113210131 in words is "two hundred thirteen billion, one hundred thirteen million, two hundred ten thousand, one hundred thirty-one".