Base | Representation |
---|---|
bin | 11111000000110001110… |
… | …111100111100111000011 |
3 | 21112201211211201120200100 |
4 | 133000301313213213003 |
5 | 234404033423130223 |
6 | 4311010555453443 |
7 | 306653434605606 |
oct | 37006167474703 |
9 | 7481754646610 |
10 | 2131140442563 |
11 | 7518a2248330 |
12 | 2a5042757283 |
13 | 125c727a9992 |
14 | 7520d5c433d |
15 | 3a681015043 |
hex | 1f031de79c3 |
2131140442563 has 48 divisors (see below), whose sum is σ = 3440245146624. Its totient is φ = 1260099046080.
The previous prime is 2131140442447. The next prime is 2131140442573. The reversal of 2131140442563 is 3652440411312.
2131140442563 is a `hidden beast` number, since 2 + 1 + 3 + 11 + 40 + 4 + 42 + 563 = 666.
It is not a de Polignac number, because 2131140442563 - 28 = 2131140442307 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2131140442573) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3383745 + ... + 3963837.
It is an arithmetic number, because the mean of its divisors is an integer number (71671773888).
Almost surely, 22131140442563 is an apocalyptic number.
2131140442563 is a deficient number, since it is larger than the sum of its proper divisors (1309104704061).
2131140442563 is a wasteful number, since it uses less digits than its factorization.
2131140442563 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 581016 (or 581013 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 36.
Adding to 2131140442563 its reverse (3652440411312), we get a palindrome (5783580853875).
The spelling of 2131140442563 in words is "two trillion, one hundred thirty-one billion, one hundred forty million, four hundred forty-two thousand, five hundred sixty-three".
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