Base | Representation |
---|---|
bin | 10011110110010000… |
… | …101001110111100001 |
3 | 2001000020012211011102 |
4 | 103312100221313201 |
5 | 322121211230423 |
6 | 13442413524145 |
7 | 1353055111211 |
oct | 236620516741 |
9 | 61006184142 |
10 | 21311430113 |
11 | 9046823966 |
12 | 41691a3655 |
13 | 20182b539c |
14 | 1062540241 |
15 | 84ae67c28 |
hex | 4f6429de1 |
21311430113 has 2 divisors, whose sum is σ = 21311430114. Its totient is φ = 21311430112.
The previous prime is 21311430103. The next prime is 21311430143. The reversal of 21311430113 is 31103411312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20093629504 + 1217800609 = 141752^2 + 34897^2 .
It is a cyclic number.
It is not a de Polignac number, because 21311430113 - 210 = 21311429089 is a prime.
It is a super-2 number, since 2×213114301132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21311430103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10655715056 + 10655715057.
It is an arithmetic number, because the mean of its divisors is an integer number (10655715057).
Almost surely, 221311430113 is an apocalyptic number.
It is an amenable number.
21311430113 is a deficient number, since it is larger than the sum of its proper divisors (1).
21311430113 is an equidigital number, since it uses as much as digits as its factorization.
21311430113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 21311430113 its reverse (31103411312), we get a palindrome (52414841425).
The spelling of 21311430113 in words is "twenty-one billion, three hundred eleven million, four hundred thirty thousand, one hundred thirteen".
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