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213117153 = 371039051
BaseRepresentation
bin11001011001111…
…10100011100001
3112212000110202220
430230332203201
5414024222103
633051501253
75165315544
oct1454764341
9485013686
10213117153
11aa332087
125b457829
13351ca932
142043885b
1513a9ac53
hexcb3e8e1

213117153 has 4 divisors (see below), whose sum is σ = 284156208. Its totient is φ = 142078100.

The previous prime is 213117137. The next prime is 213117169. The reversal of 213117153 is 351711312.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (213117137) and next prime (213117169).

It is a cyclic number.

It is not a de Polignac number, because 213117153 - 24 = 213117137 is a prime.

It is not an unprimeable number, because it can be changed into a prime (213116153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35519523 + ... + 35519528.

It is an arithmetic number, because the mean of its divisors is an integer number (71039052).

Almost surely, 2213117153 is an apocalyptic number.

It is an amenable number.

213117153 is a deficient number, since it is larger than the sum of its proper divisors (71039055).

213117153 is an equidigital number, since it uses as much as digits as its factorization.

213117153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71039054.

The product of its digits is 630, while the sum is 24.

The square root of 213117153 is about 14598.5325632407. The cubic root of 213117153 is about 597.3187330834.

Adding to 213117153 its reverse (351711312), we get a palindrome (564828465).

The spelling of 213117153 in words is "two hundred thirteen million, one hundred seventeen thousand, one hundred fifty-three".

Divisors: 1 3 71039051 213117153