Base | Representation |
---|---|
bin | 110000011101010011110010… |
… | …010110001111011001001100 |
3 | 1000221121002212010222201102211 |
4 | 300131103302112033121030 |
5 | 210413230430321102022 |
6 | 2033134044541200204 |
7 | 62614302531042403 |
oct | 6035236226173114 |
9 | 1027532763881384 |
10 | 213120343144012 |
11 | 619a791473a357 |
12 | 1baa0197860064 |
13 | 91bc215257045 |
14 | 3a8b11879663a |
15 | 1998b388ade77 |
hex | c1d4f258f64c |
213120343144012 has 12 divisors (see below), whose sum is σ = 372964917830400. Its totient is φ = 106558938049616.
The previous prime is 213120343143959. The next prime is 213120343144039. The reversal of 213120343144012 is 210441343021312.
It is a happy number.
213120343144012 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×2131203431440122 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 307991803 + ... + 308682994.
It is an arithmetic number, because the mean of its divisors is an integer number (31080409819200).
Almost surely, 2213120343144012 is an apocalyptic number.
It is an amenable number.
213120343144012 is a deficient number, since it is larger than the sum of its proper divisors (159844574686388).
213120343144012 is a wasteful number, since it uses less digits than its factorization.
213120343144012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 616761200 (or 616761198 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 213120343144012 its reverse (210441343021312), we get a palindrome (423561686165324).
The spelling of 213120343144012 in words is "two hundred thirteen trillion, one hundred twenty billion, three hundred forty-three million, one hundred forty-four thousand, twelve".
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