Base | Representation |
---|---|
bin | 11111000000110110000… |
… | …001000101101101110001 |
3 | 21112202000200200012020012 |
4 | 133000312001011231301 |
5 | 234404204232042113 |
6 | 4311021523224305 |
7 | 306655241251313 |
oct | 37006601055561 |
9 | 7482020605205 |
10 | 2131210034033 |
11 | 75192855a443 |
12 | 2a5061b18095 |
13 | 125c84034572 |
14 | 7521893b7b3 |
15 | 3a6871aeaa8 |
hex | 1f036045b71 |
2131210034033 has 2 divisors, whose sum is σ = 2131210034034. Its totient is φ = 2131210034032.
The previous prime is 2131210034011. The next prime is 2131210034137. The reversal of 2131210034033 is 3304300121312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2130233659024 + 976375009 = 1459532^2 + 31247^2 .
It is a cyclic number.
It is not a de Polignac number, because 2131210034033 - 212 = 2131210029937 is a prime.
It is not a weakly prime, because it can be changed into another prime (2131210034333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065605017016 + 1065605017017.
It is an arithmetic number, because the mean of its divisors is an integer number (1065605017017).
Almost surely, 22131210034033 is an apocalyptic number.
It is an amenable number.
2131210034033 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131210034033 is an equidigital number, since it uses as much as digits as its factorization.
2131210034033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 2131210034033 its reverse (3304300121312), we get a palindrome (5435510155345).
The spelling of 2131210034033 in words is "two trillion, one hundred thirty-one billion, two hundred ten million, thirty-four thousand, thirty-three".
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