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213122031201337 is a prime number
BaseRepresentation
bin110000011101010101010110…
…111101101010110000111001
31000221121021012210100220202111
4300131111112331222300321
5210413242404441420322
62033134524242132321
762614362416224336
oct6035252675526071
91027537183326674
10213122031201337
11619a8600595855
121baa05890510a1
1391bc423bb172b
143a8b238a4d98d
151998bd6ba4177
hexc1d556f6ac39

213122031201337 has 2 divisors, whose sum is σ = 213122031201338. Its totient is φ = 213122031201336.

The previous prime is 213122031201281. The next prime is 213122031201349. The reversal of 213122031201337 is 733102130221312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 203704227705001 + 9417803496336 = 14272499^2 + 3068844^2 .

It is a cyclic number.

It is not a de Polignac number, because 213122031201337 - 211 = 213122031199289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 213122031201299 and 213122031201308.

It is not a weakly prime, because it can be changed into another prime (213122031201637) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106561015600668 + 106561015600669.

It is an arithmetic number, because the mean of its divisors is an integer number (106561015600669).

Almost surely, 2213122031201337 is an apocalyptic number.

It is an amenable number.

213122031201337 is a deficient number, since it is larger than the sum of its proper divisors (1).

213122031201337 is an equidigital number, since it uses as much as digits as its factorization.

213122031201337 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9072, while the sum is 31.

Adding to 213122031201337 its reverse (733102130221312), we get a palindrome (946224161422649).

The spelling of 213122031201337 in words is "two hundred thirteen trillion, one hundred twenty-two billion, thirty-one million, two hundred one thousand, three hundred thirty-seven".