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213122031201481 is a prime number
BaseRepresentation
bin110000011101010101010110…
…111101101010110011001001
31000221121021012210100220221211
4300131111112331222303021
5210413242404441421411
62033134524242133121
762614362416224633
oct6035252675526311
91027537183326854
10213122031201481
11619a8600595976
121baa05890511a1
1391bc423bb180c
143a8b238a4da53
151998bd6ba4221
hexc1d556f6acc9

213122031201481 has 2 divisors, whose sum is σ = 213122031201482. Its totient is φ = 213122031201480.

The previous prime is 213122031201463. The next prime is 213122031201511. The reversal of 213122031201481 is 184102130221312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 180620402161081 + 32501629040400 = 13439509^2 + 5701020^2 .

It is a cyclic number.

It is not a de Polignac number, because 213122031201481 - 213 = 213122031193289 is a prime.

It is a super-2 number, since 2×2131220312014812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (213122031201281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106561015600740 + 106561015600741.

It is an arithmetic number, because the mean of its divisors is an integer number (106561015600741).

Almost surely, 2213122031201481 is an apocalyptic number.

It is an amenable number.

213122031201481 is a deficient number, since it is larger than the sum of its proper divisors (1).

213122031201481 is an equidigital number, since it uses as much as digits as its factorization.

213122031201481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 31.

Adding to 213122031201481 its reverse (184102130221312), we get a palindrome (397224161422793).

The spelling of 213122031201481 in words is "two hundred thirteen trillion, one hundred twenty-two billion, thirty-one million, two hundred one thousand, four hundred eighty-one".