Base | Representation |
---|---|
bin | 1100011001111100100… |
… | …0001010100000100100 |
3 | 202101002220202000001100 |
4 | 3012133020022200210 |
5 | 11442434004140134 |
6 | 241524000000100 |
7 | 21253250405430 |
oct | 3063710124044 |
9 | 671086660040 |
10 | 213123115044 |
11 | 82426495824 |
12 | 3537a600030 |
13 | 171360688c8 |
14 | a45ad379c0 |
15 | 58255e4999 |
hex | 319f20a824 |
213123115044 has 144 divisors (see below), whose sum is σ = 617699904640. Its totient is φ = 60693857280.
The previous prime is 213123115027. The next prime is 213123115081. The reversal of 213123115044 is 440511321312.
213123115044 is a `hidden beast` number, since 2 + 131 + 23 + 1 + 1 + 504 + 4 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 213123114999 and 213123115017.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 175698582 + ... + 175699794.
Almost surely, 2213123115044 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 213123115044, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (308849952320).
213123115044 is an abundant number, since it is smaller than the sum of its proper divisors (404576789596).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213123115044 is a wasteful number, since it uses less digits than its factorization.
213123115044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2930 (or 2925 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 213123115044 its reverse (440511321312), we get a palindrome (653634436356).
The spelling of 213123115044 in words is "two hundred thirteen billion, one hundred twenty-three million, one hundred fifteen thousand, forty-four".
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