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21312420132 = 2232410773673
BaseRepresentation
bin10011110110010100…
…011011100100100100
32001000022002010012210
4103312110123210210
5322121434421012
613442451043420
71353066403443
oct236624334444
961008063183
1021312420132
11904733a763
1241695a0570
132018570bb3
14106271ad5a
1584b0b123c
hex4f651b924

21312420132 has 24 divisors (see below), whose sum is σ = 49731718176. Its totient is φ = 7103748928.

The previous prime is 21312420121. The next prime is 21312420133. The reversal of 21312420132 is 23102421312.

It is a junction number, because it is equal to n+sod(n) for n = 21312420099 and 21312420108.

It is not an unprimeable number, because it can be changed into a prime (21312420133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 252448 + ... + 326120.

It is an arithmetic number, because the mean of its divisors is an integer number (2072154924).

Almost surely, 221312420132 is an apocalyptic number.

It is an amenable number.

21312420132 is an abundant number, since it is smaller than the sum of its proper divisors (28419298044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21312420132 is a wasteful number, since it uses less digits than its factorization.

21312420132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 97787 (or 97785 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 21312420132 its reverse (23102421312), we get a palindrome (44414841444).

The spelling of 21312420132 in words is "twenty-one billion, three hundred twelve million, four hundred twenty thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 24107 48214 72321 73673 96428 144642 147346 221019 289284 294692 442038 884076 1776035011 3552070022 5328105033 7104140044 10656210066 21312420132