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213130212017 is a prime number
BaseRepresentation
bin1100011001111110001…
…1001111001010110001
3202101010102002120021012
43012133203033022301
511442442313241032
6241524412040305
721253364624342
oct3063743171261
9671112076235
10213130212017
118242a4a2898
1235380a63095
1317137681cb8
14a45bc640c9
1558260476b2
hex319f8cf2b1

213130212017 has 2 divisors, whose sum is σ = 213130212018. Its totient is φ = 213130212016.

The previous prime is 213130212007. The next prime is 213130212041. The reversal of 213130212017 is 710212031312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 209471897761 + 3658314256 = 457681^2 + 60484^2 .

It is a cyclic number.

It is not a de Polignac number, because 213130212017 - 26 = 213130211953 is a prime.

It is a super-2 number, since 2×2131302120172 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213130211983 and 213130212001.

It is not a weakly prime, because it can be changed into another prime (213130212007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106565106008 + 106565106009.

It is an arithmetic number, because the mean of its divisors is an integer number (106565106009).

Almost surely, 2213130212017 is an apocalyptic number.

It is an amenable number.

213130212017 is a deficient number, since it is larger than the sum of its proper divisors (1).

213130212017 is an equidigital number, since it uses as much as digits as its factorization.

213130212017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 213130212017 its reverse (710212031312), we get a palindrome (923342243329).

The spelling of 213130212017 in words is "two hundred thirteen billion, one hundred thirty million, two hundred twelve thousand, seventeen".