Base | Representation |
---|---|
bin | 11111000000111011111… |
… | …111100100111110111000 |
3 | 21112202021200100021210201 |
4 | 133000323333210332320 |
5 | 234404410414113422 |
6 | 4311035504251544 |
7 | 306660566435206 |
oct | 37007377447670 |
9 | 7482250307721 |
10 | 2131310301112 |
11 | 75197a1135a3 |
12 | 2a508b610bb4 |
13 | 125c9ba3c7b5 |
14 | 75227d9c076 |
15 | 3a690db8727 |
hex | 1f03bfe4fb8 |
2131310301112 has 16 divisors (see below), whose sum is σ = 3996244833840. Its totient is φ = 1065645012096.
The previous prime is 2131310301061. The next prime is 2131310301119. The reversal of 2131310301112 is 2111030131312.
It is a super-2 number, since 2×21313103011122 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2131310301112.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2131310301119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333388 + ... + 2091355.
It is an arithmetic number, because the mean of its divisors is an integer number (249765302115).
Almost surely, 22131310301112 is an apocalyptic number.
It is an amenable number.
2131310301112 is a deficient number, since it is larger than the sum of its proper divisors (1864934532728).
2131310301112 is a wasteful number, since it uses less digits than its factorization.
2131310301112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2534622 (or 2534618 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 2131310301112 its reverse (2111030131312), we get a palindrome (4242340432424).
The spelling of 2131310301112 in words is "two trillion, one hundred thirty-one billion, three hundred ten million, three hundred one thousand, one hundred twelve".
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