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21313212169 is a prime number
BaseRepresentation
bin10011110110010111…
…011100111100001001
32001000100120100200111
4103312113130330021
5322122140242134
613442520034321
71353106212544
oct236627347411
961010510614
1021313212169
119047830837
1241699029a1
13201878a562
14106288585b
1584b1bac64
hex4f65dcf09

21313212169 has 2 divisors, whose sum is σ = 21313212170. Its totient is φ = 21313212168.

The previous prime is 21313212061. The next prime is 21313212191. The reversal of 21313212169 is 96121231312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13291322944 + 8021889225 = 115288^2 + 89565^2 .

It is a cyclic number.

It is not a de Polignac number, because 21313212169 - 215 = 21313179401 is a prime.

It is a super-2 number, since 2×213132121692 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21313212169.

It is not a weakly prime, because it can be changed into another prime (21313212199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656606084 + 10656606085.

It is an arithmetic number, because the mean of its divisors is an integer number (10656606085).

Almost surely, 221313212169 is an apocalyptic number.

It is an amenable number.

21313212169 is a deficient number, since it is larger than the sum of its proper divisors (1).

21313212169 is an equidigital number, since it uses as much as digits as its factorization.

21313212169 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3888, while the sum is 31.

The spelling of 21313212169 in words is "twenty-one billion, three hundred thirteen million, two hundred twelve thousand, one hundred sixty-nine".