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213133413000 = 23353438291993
BaseRepresentation
bin1100011001111110111…
…1011100101010001000
3202101010122010012012010
43012133233130222020
511442444123204000
6241525004415520
721253434055554
oct3063757345210
9671118105163
10213133413000
1182431289832
1235381b475a0
1317138232c81
14a45c458864
15582647ad50
hex319fbdca88

213133413000 has 256 divisors, whose sum is σ = 681603436800. Its totient is φ = 55419033600.

The previous prime is 213133412977. The next prime is 213133413019. The reversal of 213133413000 is 314331312.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 106940004 + ... + 106941996.

It is an arithmetic number, because the mean of its divisors is an integer number (2662513425).

Almost surely, 2213133413000 is an apocalyptic number.

213133413000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 213133413000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (340801718400).

213133413000 is an abundant number, since it is smaller than the sum of its proper divisors (468470023800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213133413000 is a wasteful number, since it uses less digits than its factorization.

213133413000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2889 (or 2875 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 213133413000 its reverse (314331312), we get a palindrome (213447744312).

The spelling of 213133413000 in words is "two hundred thirteen billion, one hundred thirty-three million, four hundred thirteen thousand".