2131410110131 has 2 divisors, whose sum is σ = 2131410110132. Its totient is φ = 2131410110130.

The previous prime is 2131410110111. The next prime is 2131410110153. The reversal of 2131410110131 is 1310110141312.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2131410110131 - 2¹¹ = 2131410108083 is a prime.

It is a super-2 number, since 2×2131410110131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2131410110099 and 2131410110108.

It is not a weakly prime, because it can be changed into another prime (2131410110111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065705055065 + 1065705055066.

It is an arithmetic number, because the mean of its divisors is an integer number (1065705055066).

Almost surely, 2^{2131410110131} is an apocalyptic number.

2131410110131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131410110131 is an equidigital number, since it uses as much as digits as its factorization.

2131410110131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 2131410110131 its reverse (1310110141312), we get a palindrome (3441520251443).

The spelling of 2131410110131 in words is "two trillion, one hundred thirty-one billion, four hundred ten million, one hundred ten thousand, one hundred thirty-one".