Base | Representation |
---|---|
bin | 11111000001100101000… |
… | …111000000001011101011 |
3 | 21112211001202100101100111 |
4 | 133001211013000023223 |
5 | 234412314012112022 |
6 | 4311232145315151 |
7 | 310013643645544 |
oct | 37014507001353 |
9 | 7484052311314 |
10 | 2132000113387 |
11 | 7521a3534791 |
12 | 2a5242635ab7 |
13 | 12607b922a41 |
14 | 752918434cb |
15 | 3a6d1727477 |
hex | 1f0651c02eb |
2132000113387 has 2 divisors, whose sum is σ = 2132000113388. Its totient is φ = 2132000113386.
The previous prime is 2132000113367. The next prime is 2132000113421. The reversal of 2132000113387 is 7833110002312.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2132000113387 is a prime.
It is a super-2 number, since 2×21320001133872 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2132000113337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066000056693 + 1066000056694.
It is an arithmetic number, because the mean of its divisors is an integer number (1066000056694).
Almost surely, 22132000113387 is an apocalyptic number.
2132000113387 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132000113387 is an equidigital number, since it uses as much as digits as its factorization.
2132000113387 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 2132000113387 its reverse (7833110002312), we get a palindrome (9965110115699).
The spelling of 2132000113387 in words is "two trillion, one hundred thirty-two billion, one hundred thirteen thousand, three hundred eighty-seven".
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