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213203100000083 is a prime number
BaseRepresentation
bin110000011110100000110111…
…000010100101111101010011
31000221220000110121121121000012
4300132200313002211331103
5210421104422100000313
62033240052455545135
762623262366521304
oct6036406702457523
91027800417547005
10213203100000083
1161a29a21836186
121bab423298b1ab
1391c6c7359152b
143a911297247ab
15199ad7dde3da8
hexc1e8370a5f53

213203100000083 has 2 divisors, whose sum is σ = 213203100000084. Its totient is φ = 213203100000082.

The previous prime is 213203099999999. The next prime is 213203100000103. The reversal of 213203100000083 is 380000001302312.

213203100000083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 213203100000083 - 212 = 213203099995987 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (213203100002083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106601550000041 + 106601550000042.

It is an arithmetic number, because the mean of its divisors is an integer number (106601550000042).

Almost surely, 2213203100000083 is an apocalyptic number.

213203100000083 is a deficient number, since it is larger than the sum of its proper divisors (1).

213203100000083 is an equidigital number, since it uses as much as digits as its factorization.

213203100000083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 213203100000083 its reverse (380000001302312), we get a palindrome (593203101302395).

The spelling of 213203100000083 in words is "two hundred thirteen trillion, two hundred three billion, one hundred million, eighty-three", and thus it is an aban number.