Base | Representation |
---|---|
bin | 11001011010100… |
… | …11111110101011 |
3 | 112212011221011001 |
4 | 30231103332223 |
5 | 414040024112 |
6 | 33053415431 |
7 | 5166132436 |
oct | 1455237653 |
9 | 485157131 |
10 | 213204907 |
11 | aa392003 |
12 | 5b49a577 |
13 | 3522b866 |
14 | 2045c81d |
15 | 13ab6c57 |
hex | cb53fab |
213204907 has 2 divisors, whose sum is σ = 213204908. Its totient is φ = 213204906.
The previous prime is 213204881. The next prime is 213204911. The reversal of 213204907 is 709402312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213204907 - 215 = 213172139 is a prime.
It is not a weakly prime, because it can be changed into another prime (213204007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106602453 + 106602454.
It is an arithmetic number, because the mean of its divisors is an integer number (106602454).
Almost surely, 2213204907 is an apocalyptic number.
213204907 is a deficient number, since it is larger than the sum of its proper divisors (1).
213204907 is an equidigital number, since it uses as much as digits as its factorization.
213204907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
The square root of 213204907 is about 14601.5378299685. The cubic root of 213204907 is about 597.4007066435.
It can be divided in two parts, 213 and 204907, that added together give a triangular number (205120 = T640).
The spelling of 213204907 in words is "two hundred thirteen million, two hundred four thousand, nine hundred seven".
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