Base | Representation |
---|---|
bin | 110000011110100111101010… |
… | …010110111001100010110011 |
3 | 1000221220201022121021100220022 |
4 | 300132213222112321202303 |
5 | 210421214401233142042 |
6 | 2033243301313234055 |
7 | 62623641361510661 |
oct | 6036475226714263 |
9 | 1027821277240808 |
10 | 213210403412147 |
11 | 61a3202a384819 |
12 | 1bab573086292b |
13 | 91c78686bb32b |
14 | 3a9161d6a1c31 |
15 | 199b15a192cd2 |
hex | c1e9ea5b98b3 |
213210403412147 has 2 divisors, whose sum is σ = 213210403412148. Its totient is φ = 213210403412146.
The previous prime is 213210403412117. The next prime is 213210403412231. The reversal of 213210403412147 is 741214304012312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213210403412147 - 220 = 213210402363571 is a prime.
It is a super-2 number, since 2×2132104034121472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (213210403412117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106605201706073 + 106605201706074.
It is an arithmetic number, because the mean of its divisors is an integer number (106605201706074).
Almost surely, 2213210403412147 is an apocalyptic number.
213210403412147 is a deficient number, since it is larger than the sum of its proper divisors (1).
213210403412147 is an equidigital number, since it uses as much as digits as its factorization.
213210403412147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 35.
Adding to 213210403412147 its reverse (741214304012312), we get a palindrome (954424707424459).
The spelling of 213210403412147 in words is "two hundred thirteen trillion, two hundred ten billion, four hundred three million, four hundred twelve thousand, one hundred forty-seven".
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