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213210403412147 is a prime number
BaseRepresentation
bin110000011110100111101010…
…010110111001100010110011
31000221220201022121021100220022
4300132213222112321202303
5210421214401233142042
62033243301313234055
762623641361510661
oct6036475226714263
91027821277240808
10213210403412147
1161a3202a384819
121bab573086292b
1391c78686bb32b
143a9161d6a1c31
15199b15a192cd2
hexc1e9ea5b98b3

213210403412147 has 2 divisors, whose sum is σ = 213210403412148. Its totient is φ = 213210403412146.

The previous prime is 213210403412117. The next prime is 213210403412231. The reversal of 213210403412147 is 741214304012312.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 213210403412147 - 220 = 213210402363571 is a prime.

It is a super-2 number, since 2×2132104034121472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (213210403412117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106605201706073 + 106605201706074.

It is an arithmetic number, because the mean of its divisors is an integer number (106605201706074).

Almost surely, 2213210403412147 is an apocalyptic number.

213210403412147 is a deficient number, since it is larger than the sum of its proper divisors (1).

213210403412147 is an equidigital number, since it uses as much as digits as its factorization.

213210403412147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32256, while the sum is 35.

Adding to 213210403412147 its reverse (741214304012312), we get a palindrome (954424707424459).

The spelling of 213210403412147 in words is "two hundred thirteen trillion, two hundred ten billion, four hundred three million, four hundred twelve thousand, one hundred forty-seven".