Base | Representation |
---|---|
bin | 10011110110110101… |
… | …100111100101110001 |
3 | 2001000220110010100022 |
4 | 103312311213211301 |
5 | 322131201320423 |
6 | 13443401333225 |
7 | 1353233350016 |
oct | 236665474561 |
9 | 61026403308 |
10 | 21321120113 |
11 | 9051242127 |
12 | 4170497215 |
13 | 201a2c8b07 |
14 | 106394370d |
15 | 84bc2ddc8 |
hex | 4f6d67971 |
21321120113 has 2 divisors, whose sum is σ = 21321120114. Its totient is φ = 21321120112.
The previous prime is 21321120109. The next prime is 21321120133. The reversal of 21321120113 is 31102112312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10726123489 + 10594996624 = 103567^2 + 102932^2 .
It is a cyclic number.
It is not a de Polignac number, because 21321120113 - 22 = 21321120109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21321120091 and 21321120100.
It is not a weakly prime, because it can be changed into another prime (21321120133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10660560056 + 10660560057.
It is an arithmetic number, because the mean of its divisors is an integer number (10660560057).
Almost surely, 221321120113 is an apocalyptic number.
It is an amenable number.
21321120113 is a deficient number, since it is larger than the sum of its proper divisors (1).
21321120113 is an equidigital number, since it uses as much as digits as its factorization.
21321120113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 21321120113 its reverse (31102112312), we get a palindrome (52423232425).
The spelling of 21321120113 in words is "twenty-one billion, three hundred twenty-one million, one hundred twenty thousand, one hundred thirteen".
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