Base | Representation |
---|---|
bin | 11111000001110010111… |
… | …000100110101110100011 |
3 | 21112211122212012211012112 |
4 | 133001302320212232203 |
5 | 234413302143021011 |
6 | 4311311122545535 |
7 | 310022451221255 |
oct | 37016270465643 |
9 | 7484585184175 |
10 | 2132231220131 |
11 | 752301a336a1 |
12 | 2a52a7b082ab |
13 | 1260b777b9ac |
14 | 752b4401cd5 |
15 | 3a6e6b7858b |
hex | 1f072e26ba3 |
2132231220131 has 2 divisors, whose sum is σ = 2132231220132. Its totient is φ = 2132231220130.
The previous prime is 2132231220121. The next prime is 2132231220149. The reversal of 2132231220131 is 1310221322312.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2132231220131 is a prime.
It is a super-2 number, since 2×21322312201312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2132231220097 and 2132231220106.
It is not a weakly prime, because it can be changed into another prime (2132231220121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066115610065 + 1066115610066.
It is an arithmetic number, because the mean of its divisors is an integer number (1066115610066).
Almost surely, 22132231220131 is an apocalyptic number.
2132231220131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132231220131 is an equidigital number, since it uses as much as digits as its factorization.
2132231220131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 2132231220131 its reverse (1310221322312), we get a palindrome (3442452542443).
The spelling of 2132231220131 in words is "two trillion, one hundred thirty-two billion, two hundred thirty-one million, two hundred twenty thousand, one hundred thirty-one".
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