Base | Representation |
---|---|
bin | 11111000001110111000… |
… | …000010010101110101010 |
3 | 21112211211200021200122111 |
4 | 133001313000102232222 |
5 | 234413422342003414 |
6 | 4311322032312534 |
7 | 310024250606254 |
oct | 37016700225652 |
9 | 7484750250574 |
10 | 2132300344234 |
11 | 752337a56655 |
12 | 2a53070a274a |
13 | 1260c8ba1928 |
14 | 752bd676cd4 |
15 | 3a6ecc7e8c4 |
hex | 1f077012baa |
2132300344234 has 4 divisors (see below), whose sum is σ = 3198450516354. Its totient is φ = 1066150172116.
The previous prime is 2132300344231. The next prime is 2132300344241. The reversal of 2132300344234 is 4324430032312.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1832273568225 + 300026776009 = 1353615^2 + 547747^2 .
It is a junction number, because it is equal to n+sod(n) for n = 2132300344196 and 2132300344205.
It is not an unprimeable number, because it can be changed into a prime (2132300344231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 533075086057 + ... + 533075086060.
Almost surely, 22132300344234 is an apocalyptic number.
2132300344234 is a deficient number, since it is larger than the sum of its proper divisors (1066150172120).
2132300344234 is a wasteful number, since it uses less digits than its factorization.
2132300344234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1066150172119.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 2132300344234 its reverse (4324430032312), we get a palindrome (6456730376546).
The spelling of 2132300344234 in words is "two trillion, one hundred thirty-two billion, three hundred million, three hundred forty-four thousand, two hundred thirty-four".
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