Base | Representation |
---|---|
bin | 1100011010010110100… |
… | …0101101111101010011 |
3 | 202101101112012210022111 |
4 | 3012211220231331103 |
5 | 11443144432442042 |
6 | 241542500250151 |
7 | 21256044514351 |
oct | 3064550557523 |
9 | 671345183274 |
10 | 213232312147 |
11 | 82482099168 |
12 | 353ab0a0957 |
13 | 1715287c68a |
14 | a46b6407d1 |
15 | 582eeb4517 |
hex | 31a5a2df53 |
213232312147 has 2 divisors, whose sum is σ = 213232312148. Its totient is φ = 213232312146.
The previous prime is 213232312133. The next prime is 213232312151. The reversal of 213232312147 is 741213232312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213232312147 - 231 = 211084828499 is a prime.
It is not a weakly prime, because it can be changed into another prime (213232312157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106616156073 + 106616156074.
It is an arithmetic number, because the mean of its divisors is an integer number (106616156074).
Almost surely, 2213232312147 is an apocalyptic number.
213232312147 is a deficient number, since it is larger than the sum of its proper divisors (1).
213232312147 is an equidigital number, since it uses as much as digits as its factorization.
213232312147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12096, while the sum is 31.
Adding to 213232312147 its reverse (741213232312), we get a palindrome (954445544459).
The spelling of 213232312147 in words is "two hundred thirteen billion, two hundred thirty-two million, three hundred twelve thousand, one hundred forty-seven".
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