21323423141131 has 2 divisors, whose sum is σ = 21323423141132. Its totient is φ = 21323423141130.

The previous prime is 21323423141113. The next prime is 21323423141173. The reversal of 21323423141131 is 13114132432312.

Together with previous prime (21323423141113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21323423141131 - 2⁵ = 21323423141099 is a prime.

It is a super-2 number, since 2×21323423141131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21323423141093 and 21323423141102.

It is not a weakly prime, because it can be changed into another prime (21323423141191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10661711570565 + 10661711570566.

It is an arithmetic number, because the mean of its divisors is an integer number (10661711570566).

Almost surely, 2^{21323423141131} is an apocalyptic number.

21323423141131 is a deficient number, since it is larger than the sum of its proper divisors (1).

21323423141131 is an equidigital number, since it uses as much as digits as its factorization.

21323423141131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10368, while the sum is 31.

Adding to 21323423141131 its reverse (13114132432312), we get a palindrome (34437555573443).

The spelling of 21323423141131 in words is "twenty-one trillion, three hundred twenty-three billion, four hundred twenty-three million, one hundred forty-one thousand, one hundred thirty-one".