Base | Representation |
---|---|
bin | 11111000001111110010… |
… | …001111010010000011101 |
3 | 21112212011011221220221021 |
4 | 133001332101322100131 |
5 | 234414200113344401 |
6 | 4311342112404141 |
7 | 310030262234104 |
oct | 37017621722035 |
9 | 7485134856837 |
10 | 2132422403101 |
11 | 75239a944251 |
12 | 2a533bb46651 |
13 | 126118269a03 |
14 | 752d196b03b |
15 | 3a7088402a1 |
hex | 1f07e47a41d |
2132422403101 has 4 divisors (see below), whose sum is σ = 2144335377600. Its totient is φ = 2120509428604.
The previous prime is 2132422403047. The next prime is 2132422403107. The reversal of 2132422403101 is 1013042242312.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2132422403101 - 239 = 1582666589213 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2132422403107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5956486981 + ... + 5956487338.
It is an arithmetic number, because the mean of its divisors is an integer number (536083844400).
Almost surely, 22132422403101 is an apocalyptic number.
It is an amenable number.
2132422403101 is a deficient number, since it is larger than the sum of its proper divisors (11912974499).
2132422403101 is a wasteful number, since it uses less digits than its factorization.
2132422403101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11912974498.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2132422403101 its reverse (1013042242312), we get a palindrome (3145464645413).
The spelling of 2132422403101 in words is "two trillion, one hundred thirty-two billion, four hundred twenty-two million, four hundred three thousand, one hundred one".
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