Base | Representation |
---|---|
bin | 11111000001111111010… |
… | …110101110010111100011 |
3 | 21112212012102220102010012 |
4 | 133001333112232113203 |
5 | 234414214223123324 |
6 | 4311343555155135 |
7 | 310030601455454 |
oct | 37017726562743 |
9 | 7485172812105 |
10 | 2132440442339 |
11 | 7523aa045409 |
12 | 2a5345ba5aab |
13 | 12611bc1480c |
14 | 752d410512b |
15 | 3a70a20520e |
hex | 1f07f5ae5e3 |
2132440442339 has 2 divisors, whose sum is σ = 2132440442340. Its totient is φ = 2132440442338.
The previous prime is 2132440442323. The next prime is 2132440442383. The reversal of 2132440442339 is 9332440442312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2132440442339 - 24 = 2132440442323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2132440442296 and 2132440442305.
It is not a weakly prime, because it can be changed into another prime (2132440447339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066220221169 + 1066220221170.
It is an arithmetic number, because the mean of its divisors is an integer number (1066220221170).
Almost surely, 22132440442339 is an apocalyptic number.
2132440442339 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132440442339 is an equidigital number, since it uses as much as digits as its factorization.
2132440442339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 497664, while the sum is 41.
The spelling of 2132440442339 in words is "two trillion, one hundred thirty-two billion, four hundred forty million, four hundred forty-two thousand, three hundred thirty-nine".
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