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21325131313019 is a prime number
BaseRepresentation
bin1001101100101001001001…
…11000000110111101111011
32210111122220001210221021222
410312110210320012331323
510243342332104004034
6113204344033022255
74330455430234412
oct466244470067573
983448801727258
1021325131313019
116881a34754706
122484b533b498b
13bb8c49b9c9a1
1453a1db3b2479
1526eab026b12e
hex136524e06f7b

21325131313019 has 2 divisors, whose sum is σ = 21325131313020. Its totient is φ = 21325131313018.

The previous prime is 21325131312943. The next prime is 21325131313033. The reversal of 21325131313019 is 91031313152312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21325131313019 - 220 = 21325130264443 is a prime.

It is a super-2 number, since 2×213251313130192 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21325131313019.

It is not a weakly prime, because it can be changed into another prime (21325131313099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10662565656509 + 10662565656510.

It is an arithmetic number, because the mean of its divisors is an integer number (10662565656510).

Almost surely, 221325131313019 is an apocalyptic number.

21325131313019 is a deficient number, since it is larger than the sum of its proper divisors (1).

21325131313019 is an equidigital number, since it uses as much as digits as its factorization.

21325131313019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14580, while the sum is 35.

The spelling of 21325131313019 in words is "twenty-one trillion, three hundred twenty-five billion, one hundred thirty-one million, three hundred thirteen thousand, nineteen".