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213253504135 = 576092957261
BaseRepresentation
bin1100011010011011100…
…1100011110010000111
3202101110000002110020221
43012212321203302013
511443220344113020
6241544534405211
721256422606520
oct3064671436207
9671400073227
10213253504135
1182493053001
12353b6200807
131715708c509
14a470399847
155831c9d6aa
hex31a6e63c87

213253504135 has 8 divisors (see below), whose sum is σ = 292461948576. Its totient is φ = 146230974240.

The previous prime is 213253504129. The next prime is 213253504159. The reversal of 213253504135 is 531405352312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 213253504135 - 29 = 213253503623 is a prime.

It is a super-3 number, since 3×2132535041353 (a number of 35 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 213253504135.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3046478596 + ... + 3046478665.

It is an arithmetic number, because the mean of its divisors is an integer number (36557743572).

Almost surely, 2213253504135 is an apocalyptic number.

213253504135 is a deficient number, since it is larger than the sum of its proper divisors (79208444441).

213253504135 is an equidigital number, since it uses as much as digits as its factorization.

213253504135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6092957273.

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 213253504135 its reverse (531405352312), we get a palindrome (744658856447).

The spelling of 213253504135 in words is "two hundred thirteen billion, two hundred fifty-three million, five hundred four thousand, one hundred thirty-five".

Divisors: 1 5 7 35 6092957261 30464786305 42650700827 213253504135