Base | Representation |
---|---|
bin | 1001101100110110001110… |
… | …10000111001101011010111 |
3 | 2210112100000021000011012120 |
4 | 10312123013100321223113 |
5 | 10244001221034012341 |
6 | 113211504342351023 |
7 | 4331124403032030 |
oct | 466330720715327 |
9 | 83470007004176 |
10 | 21332150688471 |
11 | 6884a06a32347 |
12 | 248639212b473 |
13 | bb97c81ca99c |
14 | 53a6a5733a87 |
15 | 26ed71611066 |
hex | 1366c7439ad7 |
21332150688471 has 32 divisors (see below), whose sum is σ = 32742934156800. Its totient is φ = 12101016245760.
The previous prime is 21332150688389. The next prime is 21332150688491. The reversal of 21332150688471 is 17488605123312.
It is not a de Polignac number, because 21332150688471 - 223 = 21332142299863 is a prime.
It is a super-3 number, since 3×213321506884713 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21332150688491) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 32723235 + ... + 33368763.
It is an arithmetic number, because the mean of its divisors is an integer number (1023216692400).
Almost surely, 221332150688471 is an apocalyptic number.
21332150688471 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
21332150688471 is a deficient number, since it is larger than the sum of its proper divisors (11410783468329).
21332150688471 is a wasteful number, since it uses less digits than its factorization.
21332150688471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 656999.
The product of its (nonzero) digits is 1935360, while the sum is 51.
The spelling of 21332150688471 in words is "twenty-one trillion, three hundred thirty-two billion, one hundred fifty million, six hundred eighty-eight thousand, four hundred seventy-one".
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