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213323112133 = 807892640497
BaseRepresentation
bin1100011010101100001…
…1000101111011000101
3202101121212001220110221
43012223003011323011
511443341204042013
6241555502344341
721261226351345
oct3065303057305
9671555056427
10213323112133
118251937657a
123541558b0b1
1317168621791
14a479718d25
155837e4d08d
hex31ab0c5ec5

213323112133 has 4 divisors (see below), whose sum is σ = 213325833420. Its totient is φ = 213320390848.

The previous prime is 213323112061. The next prime is 213323112221. The reversal of 213323112133 is 331211323312.

213323112133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13619590209 + 199703521924 = 116703^2 + 446882^2 .

It is a cyclic number.

It is not a de Polignac number, because 213323112133 - 29 = 213323111621 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213323112098 and 213323112107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213323112433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1239460 + ... + 1401037.

It is an arithmetic number, because the mean of its divisors is an integer number (53331458355).

Almost surely, 2213323112133 is an apocalyptic number.

It is an amenable number.

213323112133 is a deficient number, since it is larger than the sum of its proper divisors (2721287).

213323112133 is an equidigital number, since it uses as much as digits as its factorization.

213323112133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2721286.

The product of its digits is 1944, while the sum is 25.

Adding to 213323112133 its reverse (331211323312), we get a palindrome (544534435445).

The spelling of 213323112133 in words is "two hundred thirteen billion, three hundred twenty-three million, one hundred twelve thousand, one hundred thirty-three".

Divisors: 1 80789 2640497 213323112133